# So, what's the velocity of a sheep in a vacuum?

## Plus, the size of Wales in cubic furlongs

### Area

The standard unit of area shall be the nanoWales, defined as 1nWa, representing 0.0000207km2 or 20.78m2, 5.195 Thai talang wah or 28.99 Old Spanish square vara. The microWales, milliWales and Wales (Wa) are, naturally, accepted multiples of the base nanoWales.

• Football pitch = 194.89nWa
• Wales = 1,000,000,000nWa
• Belgium = 1.47Wa
• Democratic Republic of Congo = 113.3Wa
• Known universe (rolled out flat) = 19468502x1012x10256Wa

### Example:

• The eruption of Vesuvius took out an area of 13 milliWales, although the effects of the blast were felt up to a thousand brontosauruses away. Survivors reported rocks and pumice the size of Bulgarian airbags falling from the sky for three days before the tragedy, and experts have calculated the total debris would fill around 120,000 Olympic-sized swimming pools.

### Velocity of sheep in a vacuum

The theoretical maximum velocity of a sheep in a vacuum is expressed in sheepsecs (Ssx), calculated as follows:

Speed of light (c) divided by wooldrag (Wd) + Welshmen (Wm), where wooldrag is a species-defined drag coefficient determined by the length and pliability of the fleece and Welshmen is the number of locals who have turned up in their wellies, and are hanging on for dear life.

Wooldrags have recently been calculated by researchers at CERN, and the latest experiments shed some light on the phenomenon, but it is still mysterious. The effect is similar to friction here on Earth, but is due to the interaction of the wool and fluctuations in the quantum vacuum. Researchers have applied to the EU for further funding, but it has been put on hold as a result of the recent outbreak of foot and mouth disease.

For example, an unshorn Welsh Mountain Badger Face, with a wooldrag of 67, chased by three Welshmen will ultimately attain a Ssx of c/(67+3), or 4,282.74 km/sec.

Alternatively, a newly-clipped Finnish Landrace, with a wooldrag of 23, worried by just one Welshman has a theoretical Ssx of c/(23+1), or 12,491 km/sec.

Clearly, the difference in these two results means that a compromise standard is required. The El Reg Ssx uses the classic Cheviot as its sheep of choice, with a wooldrag of 50. Wm is in this case 0, since everyone knows that Welshmen do not in fact have intimate relations with sheep and any reference to the same is just a cheap attempt to drum up laughs.

The Vulture Central standard velocity for a sheep in a vacuum is, therefore, c/(50+0), or 5,995 km/sec.

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